On the diophantine equation (x^2+1)(y^2+1)=(z^2+1)^2

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In their paper [4],A. Schinzel and W. Sierpinski have investigated the diophantine equaion (x^2- 1)(y^2-1)=(z^2-1)^2. In this paper,we shall investigate an analogous equation (x^2+1)(y^2+1)=(z^2+1)^2.

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