Method of estimating exponent in volume equation with a single variable (I)

DOI Web Site

Bibliographic Information

Other Title
  • 1変数材積式の羃指数の推定法 (I)
  • 1変数材積式の冪指数の推定法-1-順序統計を用いた2点推定の理論
  • 1 ヘンスウ ザイセキシキ ノ ベキシスウ ノ スイテイホウ 1 ジュンジョ
  • 順序統計を用いた2点推定の理論
  • Theory of two points estimation based on order statistics

Search this article

Description

Volume equation, (volume)=a (d. b. h.)b, is expressed as linear form in logarithmic expansion, so it is mathematically determined by fixing the values of volume for two points d. b. h. In order to estimate b from small size samples, the method is proposed to select sample trees from two diameter classes located at a suitable distance from each other on the distribution of d. b. h. The variance of estimate of b, _??_, is given as Var. (_??_)=(λL2+λs2) σe2/(xL-xs)2, where xL=log DL, xs=log Ds, and σe2=error variance. λL and λL, are the coefficients on standard deviations of order statistics for each diameter class. Moreover, DL and Ds are large and small diameter, respectively. The best estimate will be obtained when the following xL' and xs' are obtained within the two diameter classes of DL and Ds, respectively. XL'=m+√2σx, xs'=m-√2σx. Liz. In those equations, the mean and the standard deviation of log D are denoted as m and σx, respectively. If sample trees were selected appropriately, a reasonable estimate could be obtained by using this method with small size samples.

Journal

Details 詳細情報について

Report a problem

Back to top